So who's HWeezy now ;p

The hardy-weinberg equation was created to find out the amount of alleles and amount of combinations of alleles in a gene pool (or population) given that it is a "perfect" population. A "perfect" population means that there is no natural selection or flaws in mating; mating is purely random.

My given q^2 is .15 and my given population is 1000.

q^2 is the homozygous reccessesive allele combination (qq).

with that information, I can find out the homozygous dominant allele combination (PP), heterozygous allele combination (Pq), dominant allele (p), and recessive allele (q).. I can also find the amount of individuals in the population that has each certain allele combination.

My calculations broken down step by step...

Since q^2 is the homozygouse recessive allele combination, to find the receissive allele alone, you square root q2.

q2= .15 ---> q= .39

Now that I have found q, I must find p. to find that, I subtract .39 from 1.0. I subtract .39 from 1.0 because q+p must equal 1. 

1.0 - .39= .61 

p= .61

To find p^2, I square p which was .61. I now have p^2,  q^2, q, and p. With this information , I can now complete the hardy-weinberg equation. Which is, p^2 + 2(p)(q) + q^2.

.37 + 2(.61)(.39) + .15

or

.37 + .48 +.15

Now, we have a completed equation and a given population (1000), we can find several characteristics of a population, which we have already done! however, taking it a step forward, I will also find how many individuals are homozygous dominant, heterozygous, and homozygous recessive.

gathering all of my information together, I have already found...

Homozygous recessive allele frequency: q^2= .15 --> 15%

Homozygous dominant allele frequency: p^2= .37 --> 37%

Heterozygous frequency: 2(p)(q)= .48 --> 48%

Recessive allele frequency: q= .39 --> 39%

Dominant allele frequency: p= .61 --> 61%

Now to find how much individuals in the population that are homozygous recessive, dominant, or heterozygous!! First, get q^2, p^2, and 2(p)(q). we have already found that.

Second, multiply those numbers with 1000 (since that is our given population) to find how many individuals in the population have that gene combination.

q^2 (homozygous recessive): .15 x 1000= 150 individuals

p^2 (homozygous dominant): .37 x 1000= 370 individuals

2(p)(q) (heterzygous): .48 x 1000= 480 individuals

now we are finished!!

summed up, with a hardy-weinberg equation, a given q^2, and a given population number, we can find out several characteristics involving the gene pool of the population.

The recent lab experiment with the California black worms was more than interesting. Looking so closely to through the worms' body and seeing their blood flow made me feel cool.

So, our assignment was to figure out which group had a stimulant, depressant, and which was normal out of three groups of worms that was immersed in those solutions for a few weeks.

It was hypothesized that the stimulant would make the blood flow of the worms faster, the depressant would make the blood flow slower, and the normal solution would supposedly make the blow flow "normal".

Out of my lab group's experiment, I can conclude  that Group B had the solution of the stimulant. Group A, has the normal solution. And, Group C has the depressant.

As a class, we shared all ou data so we could also compare to see if our results would be similar to others. Majority had about the same kind of results where group B would have the larger quantity numbers compare to others while group A would have he least.

My lab group had come up with group A's results at 28, 28, 31, 33, and 27. Group B's results would be 33, 38, 34, 37, and 33. Group C had: 35, 24, 31, 29, and 32. Group A had an average of 24. Group B had an average of 28.2. Group C had an average of 23.8.

I believe that group C has the solution of the depressant because the average pulse of the worms was the least. Although nearly neck and neck with group A, the numbers don't lie. Surprisingly, us group members actually thought group A had the depressant because when we observed by eye, it seemed that the pulse was slower with them.

First post.

Selfies?

:( I don't have access to under my circumstances but here is a sad picture of my favorite anime instead

(ay at least it is a picture right)